Base | Representation |
---|---|
bin | 11000011010111010001100… |
… | …00110011110001010010000 |
3 | 21001010210001121222221021012 |
4 | 30031131012012132022100 |
5 | 24014314424431002113 |
6 | 310113545125550052 |
7 | 14211531420160313 |
oct | 1415350606361220 |
9 | 231123047887235 |
10 | 53701152203408 |
11 | 16124592483986 |
12 | 6033787275328 |
13 | 23c6cc631aa78 |
14 | d3921485297a |
15 | 631d546a4aa8 |
hex | 30d74619e290 |
53701152203408 has 320 divisors, whose sum is σ = 117386950754304. Its totient is φ = 23707157760000.
The previous prime is 53701152203401. The next prime is 53701152203429. The reversal of 53701152203408 is 80430225110735.
It is not an unprimeable number, because it can be changed into a prime (53701152203401) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 4589443958 + ... + 4589455658.
Almost surely, 253701152203408 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 53701152203408, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (58693475377152).
53701152203408 is an abundant number, since it is smaller than the sum of its proper divisors (63685798550896).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53701152203408 is a wasteful number, since it uses less digits than its factorization.
53701152203408 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12014 (or 12008 counting only the distinct ones).
The product of its (nonzero) digits is 201600, while the sum is 41.
Adding to 53701152203408 its sum of digits (41), we get a square (53701152203449 = 73281072).
The spelling of 53701152203408 in words is "fifty-three trillion, seven hundred one billion, one hundred fifty-two million, two hundred three thousand, four hundred eight".
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