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5371258541 = 11488296231
BaseRepresentation
bin1010000000010011…
…01110011010101101
3111212022222012112112
411000021232122231
542000020233131
62244552413405
7250050641615
oct50011563255
914768865475
105371258541
112306a32050
12105a9a7265
13677a48cbc
1438d503a45
1521683e02b
hex14026e6ad

5371258541 has 4 divisors (see below), whose sum is σ = 5859554784. Its totient is φ = 4882962300.

The previous prime is 5371258537. The next prime is 5371258567. The reversal of 5371258541 is 1458521735.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5371258541 - 22 = 5371258537 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5371258531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 244148105 + ... + 244148126.

It is an arithmetic number, because the mean of its divisors is an integer number (1464888696).

Almost surely, 25371258541 is an apocalyptic number.

It is an amenable number.

5371258541 is a deficient number, since it is larger than the sum of its proper divisors (488296243).

5371258541 is a wasteful number, since it uses less digits than its factorization.

5371258541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 488296242.

The product of its digits is 168000, while the sum is 41.

The square root of 5371258541 is about 73288.8705125137. The cubic root of 5371258541 is about 1751.2924918130.

The spelling of 5371258541 in words is "five billion, three hundred seventy-one million, two hundred fifty-eight thousand, five hundred forty-one".

Divisors: 1 11 488296231 5371258541