Base | Representation |
---|---|
bin | 1100110011100… |
… | …1111000001011 |
3 | 10202001222100211 |
4 | 3030321320023 |
5 | 102222330233 |
6 | 5155141551 |
7 | 1221364606 |
oct | 314717013 |
9 | 122058324 |
10 | 53714443 |
11 | 28358502 |
12 | 15ba48b7 |
13 | b188cc3 |
14 | 71c333d |
15 | 4ab05cd |
hex | 3339e0b |
53714443 has 2 divisors, whose sum is σ = 53714444. Its totient is φ = 53714442.
The previous prime is 53714383. The next prime is 53714447. The reversal of 53714443 is 34441735.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53714443 - 213 = 53706251 is a prime.
It is not a weakly prime, because it can be changed into another prime (53714447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26857221 + 26857222.
It is an arithmetic number, because the mean of its divisors is an integer number (26857222).
Almost surely, 253714443 is an apocalyptic number.
53714443 is a deficient number, since it is larger than the sum of its proper divisors (1).
53714443 is an equidigital number, since it uses as much as digits as its factorization.
53714443 is an evil number, because the sum of its binary digits is even.
The product of its digits is 20160, while the sum is 31.
The square root of 53714443 is about 7329.0137808576. The cubic root of 53714443 is about 377.3088791777.
It can be divided in two parts, 537 and 14443, that multiplied together give a triangular number (7755891 = T3938).
The spelling of 53714443 in words is "fifty-three million, seven hundred fourteen thousand, four hundred forty-three".
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