Base | Representation |
---|---|
bin | 110010000001101010… |
… | …111110101001000011 |
3 | 12010122111111120211001 |
4 | 302001222332221003 |
5 | 1340002033310133 |
6 | 40402033432431 |
7 | 3611053054153 |
oct | 620152765103 |
9 | 163574446731 |
10 | 53715135043 |
11 | 2086487aa99 |
12 | a4b110b717 |
13 | 50b066259b |
14 | 2857cd0763 |
15 | 15e5aea87d |
hex | c81abea43 |
53715135043 has 2 divisors, whose sum is σ = 53715135044. Its totient is φ = 53715135042.
The previous prime is 53715135037. The next prime is 53715135079. The reversal of 53715135043 is 34053151735.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53715135043 is a prime.
It is a super-2 number, since 2×537151350432 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 53715134993 and 53715135011.
It is not a weakly prime, because it can be changed into another prime (53715105043) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26857567521 + 26857567522.
It is an arithmetic number, because the mean of its divisors is an integer number (26857567522).
Almost surely, 253715135043 is an apocalyptic number.
53715135043 is a deficient number, since it is larger than the sum of its proper divisors (1).
53715135043 is an equidigital number, since it uses as much as digits as its factorization.
53715135043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 94500, while the sum is 37.
Adding to 53715135043 its reverse (34053151735), we get a palindrome (87768286778).
The spelling of 53715135043 in words is "fifty-three billion, seven hundred fifteen million, one hundred thirty-five thousand, forty-three".
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