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53715135403 is a prime number
BaseRepresentation
bin110010000001101010…
…111110101110101011
312010122111111121022101
4302001222332232223
51340002033313103
640402033434231
73611053055206
oct620152765653
9163574447271
1053715135403
1120864880296
12a4b110b977
1350b06627b7
142857cd093d
1515e5aeaa1d
hexc81abebab

53715135403 has 2 divisors, whose sum is σ = 53715135404. Its totient is φ = 53715135402.

The previous prime is 53715135389. The next prime is 53715135431. The reversal of 53715135403 is 30453151735.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 53715135403 - 25 = 53715135371 is a prime.

It is not a weakly prime, because it can be changed into another prime (53715135493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26857567701 + 26857567702.

It is an arithmetic number, because the mean of its divisors is an integer number (26857567702).

Almost surely, 253715135403 is an apocalyptic number.

53715135403 is a deficient number, since it is larger than the sum of its proper divisors (1).

53715135403 is an equidigital number, since it uses as much as digits as its factorization.

53715135403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 94500, while the sum is 37.

The spelling of 53715135403 in words is "fifty-three billion, seven hundred fifteen million, one hundred thirty-five thousand, four hundred three".