Base | Representation |
---|---|
bin | 111101000101101000101000… |
… | …0111010100100110000001100 |
3 | 2121110112211110111121100210012 |
4 | 1322023101100322210300030 |
5 | 1030412203341224001030 |
6 | 5142452450345132352 |
7 | 221116153055565365 |
oct | 17213212072446014 |
9 | 2543484414540705 |
10 | 537336126000140 |
11 | 146236a75892025 |
12 | 5032341148a0b8 |
13 | 1a0a976b835cac |
14 | 96992c8a36b6c |
15 | 421c52bdd5095 |
hex | 1e8b450ea4c0c |
537336126000140 has 12 divisors (see below), whose sum is σ = 1128405864600336. Its totient is φ = 214934450400048.
The previous prime is 537336126000133. The next prime is 537336126000161. The reversal of 537336126000140 is 41000621633735.
It is a super-2 number, since 2×5373361260001402 (a number of 30 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13433403149984 + ... + 13433403150023.
It is an arithmetic number, because the mean of its divisors is an integer number (94033822050028).
Almost surely, 2537336126000140 is an apocalyptic number.
It is an amenable number.
537336126000140 is an abundant number, since it is smaller than the sum of its proper divisors (591069738600196).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
537336126000140 is a wasteful number, since it uses less digits than its factorization.
537336126000140 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26866806300016 (or 26866806300014 counting only the distinct ones).
The product of its (nonzero) digits is 272160, while the sum is 41.
Adding to 537336126000140 its reverse (41000621633735), we get a palindrome (578336747633875).
The spelling of 537336126000140 in words is "five hundred thirty-seven trillion, three hundred thirty-six billion, one hundred twenty-six million, one hundred forty", and thus it is an aban number.
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