Base | Representation |
---|---|
bin | 100111000110011101001… |
… | …1001110010010011101001 |
3 | 201000202012011211222101111 |
4 | 1032030322121302103221 |
5 | 1201021404341103411 |
6 | 15232435113550321 |
7 | 1063154221451323 |
oct | 116147231622351 |
9 | 21022164758344 |
10 | 5373983925481 |
11 | 1792103910026 |
12 | 7296204153a1 |
13 | 2cc9c2821472 |
14 | 14816066c613 |
15 | 94bca13d721 |
hex | 4e33a6724e9 |
5373983925481 has 2 divisors, whose sum is σ = 5373983925482. Its totient is φ = 5373983925480.
The previous prime is 5373983925419. The next prime is 5373983925491. The reversal of 5373983925481 is 1845293893735.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5353397415081 + 20586510400 = 2313741^2 + 143480^2 .
It is a cyclic number.
It is not a de Polignac number, because 5373983925481 - 223 = 5373975536873 is a prime.
It is a super-2 number, since 2×53739839254812 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5373983925491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2686991962740 + 2686991962741.
It is an arithmetic number, because the mean of its divisors is an integer number (2686991962741).
Almost surely, 25373983925481 is an apocalyptic number.
It is an amenable number.
5373983925481 is a deficient number, since it is larger than the sum of its proper divisors (1).
5373983925481 is an equidigital number, since it uses as much as digits as its factorization.
5373983925481 is an evil number, because the sum of its binary digits is even.
The product of its digits is 195955200, while the sum is 67.
The spelling of 5373983925481 in words is "five trillion, three hundred seventy-three billion, nine hundred eighty-three million, nine hundred twenty-five thousand, four hundred eighty-one".
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