Base | Representation |
---|---|
bin | 110010000011110001… |
… | …000001100110000101 |
3 | 12010201221121212000002 |
4 | 302003301001212011 |
5 | 1340040032240222 |
6 | 40405330531045 |
7 | 3611660536316 |
oct | 620361014605 |
9 | 163657555002 |
10 | 53750274437 |
11 | 208826a0812 |
12 | a500a36a85 |
13 | 50b7a16922 |
14 | 285c83a60d |
15 | 15e8c3c392 |
hex | c83c41985 |
53750274437 has 4 divisors (see below), whose sum is σ = 53763979680. Its totient is φ = 53736569196.
The previous prime is 53750274427. The next prime is 53750274463. The reversal of 53750274437 is 73447205735.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 53750274437 - 224 = 53733497221 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53750274391 and 53750274400.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53750274427) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6846737 + ... + 6854582.
It is an arithmetic number, because the mean of its divisors is an integer number (13440994920).
Almost surely, 253750274437 is an apocalyptic number.
It is an amenable number.
53750274437 is a deficient number, since it is larger than the sum of its proper divisors (13705243).
53750274437 is a wasteful number, since it uses less digits than its factorization.
53750274437 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13705242.
The product of its (nonzero) digits is 2469600, while the sum is 47.
The spelling of 53750274437 in words is "fifty-three billion, seven hundred fifty million, two hundred seventy-four thousand, four hundred thirty-seven".
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