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5376331564481 is a prime number
BaseRepresentation
bin100111000111100011001…
…0101010100010111000001
3201000222020210100101200002
41032033012111110113001
51201041211340030411
615233504100005345
71063266336165023
oct116170625242701
921028223311602
105376331564481
1117930a9009a49
12729b76690855
132ccca8006177
1414830437c013
1594cb62c033b
hex4e3c65545c1

5376331564481 has 2 divisors, whose sum is σ = 5376331564482. Its totient is φ = 5376331564480.

The previous prime is 5376331564423. The next prime is 5376331564493. The reversal of 5376331564481 is 1844651336735.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4879857721600 + 496473842881 = 2209040^2 + 704609^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5376331564481 is a prime.

It is a super-2 number, since 2×53763315644812 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5376331564411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2688165782240 + 2688165782241.

It is an arithmetic number, because the mean of its divisors is an integer number (2688165782241).

Almost surely, 25376331564481 is an apocalyptic number.

It is an amenable number.

5376331564481 is a deficient number, since it is larger than the sum of its proper divisors (1).

5376331564481 is an equidigital number, since it uses as much as digits as its factorization.

5376331564481 is an evil number, because the sum of its binary digits is even.

The product of its digits is 21772800, while the sum is 56.

The spelling of 5376331564481 in words is "five trillion, three hundred seventy-six billion, three hundred thirty-one million, five hundred sixty-four thousand, four hundred eighty-one".