Base | Representation |
---|---|
bin | 111101001010100001001011… |
… | …0100101100101110011010011 |
3 | 2121112220222220110100020222112 |
4 | 1322111002112211211303103 |
5 | 1031004202432302141312 |
6 | 5144125051315255535 |
7 | 221215513452020453 |
oct | 17225022645456323 |
9 | 2545828813306875 |
10 | 538007309802707 |
11 | 146475689620018 |
12 | 504115075aa5ab |
13 | 1a127b43c50924 |
14 | 96bd99ac07d63 |
15 | 422ec1124ed22 |
hex | 1e95096965cd3 |
538007309802707 has 2 divisors, whose sum is σ = 538007309802708. Its totient is φ = 538007309802706.
The previous prime is 538007309802701. The next prime is 538007309802731. The reversal of 538007309802707 is 707208903700835.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 538007309802707 - 210 = 538007309801683 is a prime.
It is a super-2 number, since 2×5380073098027072 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (538007309802701) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 269003654901353 + 269003654901354.
It is an arithmetic number, because the mean of its divisors is an integer number (269003654901354).
Almost surely, 2538007309802707 is an apocalyptic number.
538007309802707 is a deficient number, since it is larger than the sum of its proper divisors (1).
538007309802707 is an equidigital number, since it uses as much as digits as its factorization.
538007309802707 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17781120, while the sum is 59.
The spelling of 538007309802707 in words is "five hundred thirty-eight trillion, seven billion, three hundred nine million, eight hundred two thousand, seven hundred seven".
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