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5381364103 = 41131252783
BaseRepresentation
bin1010000001100000…
…10001100110000111
3111220000222121202121
411000300101212013
542010112122403
62245553150411
7250232561113
oct50060214607
914800877677
105381364103
112311704555
12106225b407
13679b7691b
143909b4743
152176883bd
hex140c11987

5381364103 has 4 divisors (see below), whose sum is σ = 5512616928. Its totient is φ = 5250111280.

The previous prime is 5381364077. The next prime is 5381364113. The reversal of 5381364103 is 3014631835.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5381364103 - 29 = 5381363591 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5381364113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65626351 + ... + 65626432.

It is an arithmetic number, because the mean of its divisors is an integer number (1378154232).

Almost surely, 25381364103 is an apocalyptic number.

5381364103 is a deficient number, since it is larger than the sum of its proper divisors (131252825).

5381364103 is a wasteful number, since it uses less digits than its factorization.

5381364103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 131252824.

The product of its (nonzero) digits is 25920, while the sum is 34.

The square root of 5381364103 is about 73357.7814754509. The cubic root of 5381364103 is about 1752.3901059225.

Adding to 5381364103 its reverse (3014631835), we get a palindrome (8395995938).

The spelling of 5381364103 in words is "five billion, three hundred eighty-one million, three hundred sixty-four thousand, one hundred three".

Divisors: 1 41 131252783 5381364103