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538150643 is a prime number
BaseRepresentation
bin100000000100111…
…000011011110011
31101111121212220022
4200010320123303
52100231310033
6125222234055
716223130212
oct4004703363
91344555808
10538150643
112568545a8
1213028592b
1387651c44
1451687079
15323a2098
hex201386f3

538150643 has 2 divisors, whose sum is σ = 538150644. Its totient is φ = 538150642.

The previous prime is 538150621. The next prime is 538150663. The reversal of 538150643 is 346051835.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 538150643 - 212 = 538146547 is a prime.

It is a super-2 number, since 2×5381506432 = 579212229122626898, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (538150663) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 269075321 + 269075322.

It is an arithmetic number, because the mean of its divisors is an integer number (269075322).

Almost surely, 2538150643 is an apocalyptic number.

538150643 is a deficient number, since it is larger than the sum of its proper divisors (1).

538150643 is an equidigital number, since it uses as much as digits as its factorization.

538150643 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43200, while the sum is 35.

The square root of 538150643 is about 23198.0741226508. The cubic root of 538150643 is about 813.3946055731.

The spelling of 538150643 in words is "five hundred thirty-eight million, one hundred fifty thousand, six hundred forty-three".