Base | Representation |
---|---|
bin | 100111001001111110001… |
… | …1000011111011110000101 |
3 | 201001110200022101122010111 |
4 | 1032103330120133132011 |
5 | 1201132340013132011 |
6 | 15240124155553021 |
7 | 1063542261405022 |
oct | 116237430373605 |
9 | 21043608348114 |
10 | 5381533333381 |
11 | 17953282a7a07 |
12 | 72ab8875b771 |
13 | 3006268bb22a |
14 | 148679162549 |
15 | 94ebccd0121 |
hex | 4e4fc61f785 |
5381533333381 has 4 divisors (see below), whose sum is σ = 5615513043552. Its totient is φ = 5147553623212.
The previous prime is 5381533333349. The next prime is 5381533333403. The reversal of 5381533333381 is 1833333351835.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5381533333381 - 25 = 5381533333349 is a prime.
It is a super-2 number, since 2×53815333333812 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5381533333081) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 116989855051 + ... + 116989855096.
It is an arithmetic number, because the mean of its divisors is an integer number (1403878260888).
Almost surely, 25381533333381 is an apocalyptic number.
It is an amenable number.
5381533333381 is a deficient number, since it is larger than the sum of its proper divisors (233979710171).
5381533333381 is a wasteful number, since it uses less digits than its factorization.
5381533333381 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 233979710170.
The product of its digits is 3499200, while the sum is 49.
The spelling of 5381533333381 in words is "five trillion, three hundred eighty-one billion, five hundred thirty-three million, three hundred thirty-three thousand, three hundred eighty-one".
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