Base | Representation |
---|---|
bin | 100111001001111110001… |
… | …1000011111011110011011 |
3 | 201001110200022101122011022 |
4 | 1032103330120133132123 |
5 | 1201132340013132103 |
6 | 15240124155553055 |
7 | 1063542261405053 |
oct | 116237430373633 |
9 | 21043608348138 |
10 | 5381533333403 |
11 | 17953282a7a27 |
12 | 72ab8875b78b |
13 | 3006268bb246 |
14 | 148679162563 |
15 | 94ebccd0138 |
hex | 4e4fc61f79b |
5381533333403 has 2 divisors, whose sum is σ = 5381533333404. Its totient is φ = 5381533333402.
The previous prime is 5381533333349. The next prime is 5381533333459. The reversal of 5381533333403 is 3043333351835.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5381533333403 - 218 = 5381533071259 is a prime.
It is not a weakly prime, because it can be changed into another prime (5381533333103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2690766666701 + 2690766666702.
It is an arithmetic number, because the mean of its divisors is an integer number (2690766666702).
Almost surely, 25381533333403 is an apocalyptic number.
5381533333403 is a deficient number, since it is larger than the sum of its proper divisors (1).
5381533333403 is an equidigital number, since it uses as much as digits as its factorization.
5381533333403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1749600, while the sum is 44.
The spelling of 5381533333403 in words is "five trillion, three hundred eighty-one billion, five hundred thirty-three million, three hundred thirty-three thousand, four hundred three".
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