Base | Representation |
---|---|
bin | 100111001010110110001… |
… | …0101001101111011100111 |
3 | 201001122112012112120100012 |
4 | 1032111230111031323213 |
5 | 1201200211322221203 |
6 | 15241034412040435 |
7 | 1063636645636262 |
oct | 116255425157347 |
9 | 21048465476305 |
10 | 5383411523303 |
11 | 1796101506890 |
12 | 72b41176311b |
13 | 300865a56808 |
14 | 1487b678dcd9 |
15 | 9507cb30bd8 |
hex | 4e56c54dee7 |
5383411523303 has 32 divisors (see below), whose sum is σ = 6108807082752. Its totient is φ = 4701137414400.
The previous prime is 5383411523299. The next prime is 5383411523353. The reversal of 5383411523303 is 3033251143835.
It is a cyclic number.
It is not a de Polignac number, because 5383411523303 - 22 = 5383411523299 is a prime.
It is a super-3 number, since 3×53834115233033 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5383411523353) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 343256300 + ... + 343271982.
It is an arithmetic number, because the mean of its divisors is an integer number (190900221336).
Almost surely, 25383411523303 is an apocalyptic number.
5383411523303 is a deficient number, since it is larger than the sum of its proper divisors (725395559449).
5383411523303 is a wasteful number, since it uses less digits than its factorization.
5383411523303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 27695.
The product of its (nonzero) digits is 388800, while the sum is 41.
The spelling of 5383411523303 in words is "five trillion, three hundred eighty-three billion, four hundred eleven million, five hundred twenty-three thousand, three hundred three".
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