Base | Representation |
---|---|
bin | 1010000010000001… |
… | …01100010110011001 |
3 | 111220100002021120221 |
4 | 11001000230112121 |
5 | 42012212333433 |
6 | 2250225320041 |
7 | 250314264646 |
oct | 50100542631 |
9 | 14810067527 |
10 | 5385667993 |
11 | 2314084092 |
12 | 1063796021 |
13 | 67aa228c4 |
14 | 3913b4dcd |
15 | 217c3872d |
hex | 14102c599 |
5385667993 has 2 divisors, whose sum is σ = 5385667994. Its totient is φ = 5385667992.
The previous prime is 5385667951. The next prime is 5385668021. The reversal of 5385667993 is 3997665835.
5385667993 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2787523209 + 2598144784 = 52797^2 + 50972^2 .
It is a cyclic number.
It is not a de Polignac number, because 5385667993 - 29 = 5385667481 is a prime.
It is not a weakly prime, because it can be changed into another prime (5385667943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2692833996 + 2692833997.
It is an arithmetic number, because the mean of its divisors is an integer number (2692833997).
Almost surely, 25385667993 is an apocalyptic number.
It is an amenable number.
5385667993 is a deficient number, since it is larger than the sum of its proper divisors (1).
5385667993 is an equidigital number, since it uses as much as digits as its factorization.
5385667993 is an evil number, because the sum of its binary digits is even.
The product of its digits is 36741600, while the sum is 61.
The square root of 5385667993 is about 73387.1105372054. The cubic root of 5385667993 is about 1752.8571550658.
The spelling of 5385667993 in words is "five billion, three hundred eighty-five million, six hundred sixty-seven thousand, nine hundred ninety-three".
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