Base | Representation |
---|---|
bin | 110010001101011110… |
… | …010000011111001001 |
3 | 12011011022001121112012 |
4 | 302031132100133021 |
5 | 1340403230024412 |
6 | 40433425225305 |
7 | 3616006005602 |
oct | 621536203711 |
9 | 164138047465 |
10 | 53913126857 |
11 | 20956611197 |
12 | a547492235 |
13 | 51126957c5 |
14 | 287630cda9 |
15 | 16081a9c22 |
hex | c8d7907c9 |
53913126857 has 2 divisors, whose sum is σ = 53913126858. Its totient is φ = 53913126856.
The previous prime is 53913126847. The next prime is 53913126901. The reversal of 53913126857 is 75862131935.
53913126857 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 36073784761 + 17839342096 = 189931^2 + 133564^2 .
It is a cyclic number.
It is not a de Polignac number, because 53913126857 - 212 = 53913122761 is a prime.
It is not a weakly prime, because it can be changed into another prime (53913126847) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26956563428 + 26956563429.
It is an arithmetic number, because the mean of its divisors is an integer number (26956563429).
Almost surely, 253913126857 is an apocalyptic number.
It is an amenable number.
53913126857 is a deficient number, since it is larger than the sum of its proper divisors (1).
53913126857 is an equidigital number, since it uses as much as digits as its factorization.
53913126857 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1360800, while the sum is 50.
The spelling of 53913126857 in words is "fifty-three billion, nine hundred thirteen million, one hundred twenty-six thousand, eight hundred fifty-seven".
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