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53934373 = 199271027
BaseRepresentation
bin1100110110111…
…1100100100101
310202111011001101
43031233210211
5102301344443
65204000101
71223302033
oct315574445
9122434041
1053934373
1128498769
1216090031
13b23513c
14723d553
154b0584d
hex336f925

53934373 has 4 divisors (see below), whose sum is σ = 54205600. Its totient is φ = 53663148.

The previous prime is 53934359. The next prime is 53934401. The reversal of 53934373 is 37343935.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 37343935 = 57468787.

It is a cyclic number.

It is not a de Polignac number, because 53934373 - 221 = 51837221 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53934323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 135315 + ... + 135712.

It is an arithmetic number, because the mean of its divisors is an integer number (13551400).

Almost surely, 253934373 is an apocalyptic number.

It is an amenable number.

53934373 is a deficient number, since it is larger than the sum of its proper divisors (271227).

53934373 is a wasteful number, since it uses less digits than its factorization.

53934373 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 271226.

The product of its digits is 102060, while the sum is 37.

The square root of 53934373 is about 7344.0025190627. The cubic root of 53934373 is about 377.8231328251.

Subtracting from 53934373 its sum of digits (37), we obtain a square (53934336 = 73442).

The spelling of 53934373 in words is "fifty-three million, nine hundred thirty-four thousand, three hundred seventy-three".

Divisors: 1 199 271027 53934373