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53954151313 is a prime number
BaseRepresentation
bin110010001111111010…
…110000001110010001
312011021011020212111111
4302033322300032101
51340444230320223
640441452413321
73620014501456
oct621772601621
9164234225444
1053954151313
11209777914a7
12a559177241
13511b02a72a
14287b94b82d
15160bab030d
hexc8feb0391

53954151313 has 2 divisors, whose sum is σ = 53954151314. Its totient is φ = 53954151312.

The previous prime is 53954151289. The next prime is 53954151379. The reversal of 53954151313 is 31315145935.

53954151313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 53943314049 + 10837264 = 232257^2 + 3292^2 .

It is a cyclic number.

It is not a de Polignac number, because 53954151313 - 29 = 53954150801 is a prime.

It is a super-2 number, since 2×539541513132 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (53954151613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26977075656 + 26977075657.

It is an arithmetic number, because the mean of its divisors is an integer number (26977075657).

Almost surely, 253954151313 is an apocalyptic number.

It is an amenable number.

53954151313 is a deficient number, since it is larger than the sum of its proper divisors (1).

53954151313 is an equidigital number, since it uses as much as digits as its factorization.

53954151313 is an evil number, because the sum of its binary digits is even.

The product of its digits is 121500, while the sum is 40.

The spelling of 53954151313 in words is "fifty-three billion, nine hundred fifty-four million, one hundred fifty-one thousand, three hundred thirteen".