Search a number
-
+
53964714241 is a prime number
BaseRepresentation
bin110010010000100011…
…000011000100000001
312011021220010112010001
4302100203003010001
51341004431323431
640442511040001
73620203334254
oct622043030401
9164256115101
1053964714241
1120982746599
12a560810001
135120288599
14287d0db09b
15160c999e61
hexc908c3101

53964714241 has 2 divisors, whose sum is σ = 53964714242. Its totient is φ = 53964714240.

The previous prime is 53964714233. The next prime is 53964714301. The reversal of 53964714241 is 14241746935.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 39225783025 + 14738931216 = 198055^2 + 121404^2 .

It is a cyclic number.

It is not a de Polignac number, because 53964714241 - 23 = 53964714233 is a prime.

It is a super-2 number, since 2×539647142412 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 53964714191 and 53964714200.

It is not a weakly prime, because it can be changed into another prime (53964714841) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26982357120 + 26982357121.

It is an arithmetic number, because the mean of its divisors is an integer number (26982357121).

Almost surely, 253964714241 is an apocalyptic number.

It is an amenable number.

53964714241 is a deficient number, since it is larger than the sum of its proper divisors (1).

53964714241 is an equidigital number, since it uses as much as digits as its factorization.

53964714241 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 725760, while the sum is 46.

The spelling of 53964714241 in words is "fifty-three billion, nine hundred sixty-four million, seven hundred fourteen thousand, two hundred forty-one".