Base | Representation |
---|---|
bin | 11000100011001010100111… |
… | …00000000001111100100111 |
3 | 21002010220022122202112010201 |
4 | 30101211103200001330213 |
5 | 24033441430240131220 |
6 | 310452143443531331 |
7 | 14241163531652320 |
oct | 1421452340017447 |
9 | 232126278675121 |
10 | 53984844848935 |
11 | 16223931598420 |
12 | 607a75b389b47 |
13 | 24179977bbcb0 |
14 | d48c47c97447 |
15 | 63940a3a9d0a |
hex | 311953801f27 |
53984844848935 has 64 divisors (see below), whose sum is σ = 90761507665920. Its totient is φ = 29713588692480.
The previous prime is 53984844848933. The next prime is 53984844848947.
53984844848935 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 53984844848935 - 21 = 53984844848933 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53984844848933) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 234367120 + ... + 234597349.
It is an arithmetic number, because the mean of its divisors is an integer number (1418148557280).
Almost surely, 253984844848935 is an apocalyptic number.
53984844848935 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53984844848935 is a deficient number, since it is larger than the sum of its proper divisors (36776662816985).
53984844848935 is a wasteful number, since it uses less digits than its factorization.
53984844848935 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 468964528.
The product of its digits is 19110297600, while the sum is 82.
The spelling of 53984844848935 in words is "fifty-three trillion, nine hundred eighty-four billion, eight hundred forty-four million, eight hundred forty-eight thousand, nine hundred thirty-five".
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