Base | Representation |
---|---|
bin | 11000100011100001011100… |
… | …00011000000000000000000 |
3 | 21002012001221211121000000000 |
4 | 30101300232003000000000 |
5 | 24034142030423234210 |
6 | 310501532000000000 |
7 | 14242106336535630 |
oct | 1421605603000000 |
9 | 232161854530000 |
10 | 53997101383680 |
11 | 16229051036384 |
12 | 6081000000000 |
13 | 2418b9bb43710 |
14 | d4968b9b26c0 |
15 | 6398c6400ac0 |
hex | 311c2e0c0000 |
53997101383680 has 3040 divisors, whose sum is σ = 249646108529664. Its totient is φ = 10897456103424.
The previous prime is 53997101383663. The next prime is 53997101383711. The reversal of 53997101383680 is 8638310179935.
53997101383680 is a `hidden beast` number, since 5 + 3 + 9 + 97 + 101 + 383 + 68 + 0 = 666.
It is a Harshad number since it is a multiple of its sum of digits (63).
It is an unprimeable number.
It is a polite number, since it can be written in 159 ways as a sum of consecutive naturals, for example, 2347700060149 + ... + 2347700060171.
Almost surely, 253997101383680 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 53997101383680, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (124823054264832).
53997101383680 is an abundant number, since it is smaller than the sum of its proper divisors (195649007145984).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53997101383680 is an frugal number, since it uses more digits than its factorization.
53997101383680 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 111 (or 53 counting only the distinct ones).
The product of its (nonzero) digits is 29393280, while the sum is 63.
The spelling of 53997101383680 in words is "fifty-three trillion, nine hundred ninety-seven billion, one hundred one million, three hundred eighty-three thousand, six hundred eighty".
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