Base | Representation |
---|---|
bin | 110010010010110100… |
… | …001010011101001011 |
3 | 12011101112201012202222 |
4 | 302102310022131023 |
5 | 1341044201133103 |
6 | 40450350244255 |
7 | 3621144563402 |
oct | 622264123513 |
9 | 164345635688 |
10 | 54002755403 |
11 | 209a2169473 |
12 | a5714b668b |
13 | 512811764c |
14 | 28841a0639 |
15 | 1610eb1638 |
hex | c92d0a74b |
54002755403 has 2 divisors, whose sum is σ = 54002755404. Its totient is φ = 54002755402.
The previous prime is 54002755379. The next prime is 54002755423. The reversal of 54002755403 is 30455720045.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54002755403 is a prime.
It is a super-2 number, since 2×540027554032 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (54002755423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27001377701 + 27001377702.
It is an arithmetic number, because the mean of its divisors is an integer number (27001377702).
Almost surely, 254002755403 is an apocalyptic number.
54002755403 is a deficient number, since it is larger than the sum of its proper divisors (1).
54002755403 is an equidigital number, since it uses as much as digits as its factorization.
54002755403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 84000, while the sum is 35.
The spelling of 54002755403 in words is "fifty-four billion, two million, seven hundred fifty-five thousand, four hundred three".
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