Base | Representation |
---|---|
bin | 1100111000001… |
… | …0101000010001 |
3 | 10202122010010111 |
4 | 3032002220101 |
5 | 102311344213 |
6 | 5205401321 |
7 | 1224045436 |
oct | 316025021 |
9 | 122563114 |
10 | 54012433 |
11 | 28541382 |
12 | 16109241 |
13 | b261827 |
14 | 725db8d |
15 | 4b1da3d |
hex | 3382a11 |
54012433 has 2 divisors, whose sum is σ = 54012434. Its totient is φ = 54012432.
The previous prime is 54012397. The next prime is 54012437. The reversal of 54012433 is 33421045.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 46076944 + 7935489 = 6788^2 + 2817^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54012433 is a prime.
It is not a weakly prime, because it can be changed into another prime (54012437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27006216 + 27006217.
It is an arithmetic number, because the mean of its divisors is an integer number (27006217).
Almost surely, 254012433 is an apocalyptic number.
It is an amenable number.
54012433 is a deficient number, since it is larger than the sum of its proper divisors (1).
54012433 is an equidigital number, since it uses as much as digits as its factorization.
54012433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 22.
The square root of 54012433 is about 7349.3151381608. The cubic root of 54012433 is about 378.0053212580.
Adding to 54012433 its reverse (33421045), we get a palindrome (87433478).
It can be divided in two parts, 54012 and 433, that added together give a palindrome (54445).
The spelling of 54012433 in words is "fifty-four million, twelve thousand, four hundred thirty-three".
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