Base | Representation |
---|---|
bin | 11000100011111111011001… |
… | …10001111111110110111011 |
3 | 21002020121110211011020021001 |
4 | 30101333230301333312323 |
5 | 24034423001141324140 |
6 | 310513152031025431 |
7 | 14243216052062014 |
oct | 1421775461776673 |
9 | 232217424136231 |
10 | 54013186276795 |
11 | 16234955594679 |
12 | 608414a96b277 |
13 | 241a563381255 |
14 | d4a375d2200b |
15 | 63a0185b4e9a |
hex | 311fecc7fdbb |
54013186276795 has 32 divisors (see below), whose sum is σ = 66839992128000. Its totient is φ = 41885212226304.
The previous prime is 54013186276787. The next prime is 54013186276823. The reversal of 54013186276795 is 59767268131045.
It is a cyclic number.
It is not a de Polignac number, because 54013186276795 - 23 = 54013186276787 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3265056 + ... + 10894354.
It is an arithmetic number, because the mean of its divisors is an integer number (2088749754000).
It is a 1-persistent number, because it is pandigital, but 2⋅54013186276795 = 108026372553590 is not.
Almost surely, 254013186276795 is an apocalyptic number.
54013186276795 is a deficient number, since it is larger than the sum of its proper divisors (12826805851205).
54013186276795 is a wasteful number, since it uses less digits than its factorization.
54013186276795 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7629699.
The product of its (nonzero) digits is 76204800, while the sum is 64.
The spelling of 54013186276795 in words is "fifty-four trillion, thirteen billion, one hundred eighty-six million, two hundred seventy-six thousand, seven hundred ninety-five".
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