Base | Representation |
---|---|
bin | 110010010011011101… |
… | …001111011101111001 |
3 | 12011102021222022021201 |
4 | 302103131033131321 |
5 | 1341104430230313 |
6 | 40451413134201 |
7 | 3621335243263 |
oct | 622335173571 |
9 | 164367868251 |
10 | 54013523833 |
11 | 209a82539a5 |
12 | a57502a361 |
13 | 512a417bb9 |
14 | 28857a4b33 |
15 | 1611ddc0dd |
hex | c9374f779 |
54013523833 has 2 divisors, whose sum is σ = 54013523834. Its totient is φ = 54013523832.
The previous prime is 54013523827. The next prime is 54013523843. The reversal of 54013523833 is 33832531045.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 54013478464 + 45369 = 232408^2 + 213^2 .
It is a cyclic number.
It is not a de Polignac number, because 54013523833 - 29 = 54013523321 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 54013523792 and 54013523801.
It is not a weakly prime, because it can be changed into another prime (54013523813) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27006761916 + 27006761917.
It is an arithmetic number, because the mean of its divisors is an integer number (27006761917).
Almost surely, 254013523833 is an apocalyptic number.
It is an amenable number.
54013523833 is a deficient number, since it is larger than the sum of its proper divisors (1).
54013523833 is an equidigital number, since it uses as much as digits as its factorization.
54013523833 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129600, while the sum is 37.
The spelling of 54013523833 in words is "fifty-four billion, thirteen million, five hundred twenty-three thousand, eight hundred thirty-three".
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