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54014020003 is a prime number
BaseRepresentation
bin110010010011011111…
…001000100110100011
312011102022220111220101
4302103133020212203
51341110042120003
640451431523231
73621342410656
oct622337104643
9164368814811
1054014020003
11209a8562759
12a575229517
13512a55c9a8
14288589389d
151611e8911d
hexc937c89a3

54014020003 has 2 divisors, whose sum is σ = 54014020004. Its totient is φ = 54014020002.

The previous prime is 54014019991. The next prime is 54014020057. The reversal of 54014020003 is 30002041045.

54014020003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 54014020003 - 233 = 45424085411 is a prime.

It is not a weakly prime, because it can be changed into another prime (54014020303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27007010001 + 27007010002.

It is an arithmetic number, because the mean of its divisors is an integer number (27007010002).

Almost surely, 254014020003 is an apocalyptic number.

54014020003 is a deficient number, since it is larger than the sum of its proper divisors (1).

54014020003 is an equidigital number, since it uses as much as digits as its factorization.

54014020003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 480, while the sum is 19.

Adding to 54014020003 its reverse (30002041045), we get a palindrome (84016061048).

The spelling of 54014020003 in words is "fifty-four billion, fourteen million, twenty thousand, three".