Base | Representation |
---|---|
bin | 100111010011100000001… |
… | …1000000111110000001001 |
3 | 201010102111202202011121021 |
4 | 1032213000120013300021 |
5 | 1202001244332033003 |
6 | 15253351210312441 |
7 | 1065165426422362 |
oct | 116470030076011 |
9 | 21112452664537 |
10 | 5402001439753 |
11 | 17a2a80a8a1a6 |
12 | 732b3b428721 |
13 | 302539262089 |
14 | 14965b69ab69 |
15 | 957b9bb42bd |
hex | 4e9c0607c09 |
5402001439753 has 2 divisors, whose sum is σ = 5402001439754. Its totient is φ = 5402001439752.
The previous prime is 5402001439733. The next prime is 5402001439771. The reversal of 5402001439753 is 3579341002045.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2726038749184 + 2675962690569 = 1651072^2 + 1635837^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5402001439753 is a prime.
It is not a weakly prime, because it can be changed into another prime (5402001439733) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2701000719876 + 2701000719877.
It is an arithmetic number, because the mean of its divisors is an integer number (2701000719877).
Almost surely, 25402001439753 is an apocalyptic number.
It is an amenable number.
5402001439753 is a deficient number, since it is larger than the sum of its proper divisors (1).
5402001439753 is an equidigital number, since it uses as much as digits as its factorization.
5402001439753 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 453600, while the sum is 43.
The spelling of 5402001439753 in words is "five trillion, four hundred two billion, one million, four hundred thirty-nine thousand, seven hundred fifty-three".
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