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5402013414551 = 13415539493427
BaseRepresentation
bin100111010011100000100…
…0101110011010010010111
3201010102112121021112221022
41032213001011303102113
51202001310413231201
615253352315111355
71065165633255335
oct116470105632227
921112477245838
105402013414551
1117a2a87819026
12732b4344255b
1330253b895760
1414965d0d6b55
15957bac7c41b
hex4e9c1173497

5402013414551 has 4 divisors (see below), whose sum is σ = 5817552907992. Its totient is φ = 4986473921112.

The previous prime is 5402013414529. The next prime is 5402013414559. The reversal of 5402013414551 is 1554143102045.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5402013414551 - 26 = 5402013414487 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5402013414559) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 207769746701 + ... + 207769746726.

It is an arithmetic number, because the mean of its divisors is an integer number (1454388226998).

Almost surely, 25402013414551 is an apocalyptic number.

5402013414551 is a deficient number, since it is larger than the sum of its proper divisors (415539493441).

5402013414551 is a wasteful number, since it uses less digits than its factorization.

5402013414551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 415539493440.

The product of its (nonzero) digits is 48000, while the sum is 35.

Adding to 5402013414551 its reverse (1554143102045), we get a palindrome (6956156516596).

The spelling of 5402013414551 in words is "five trillion, four hundred two billion, thirteen million, four hundred fourteen thousand, five hundred fifty-one".

Divisors: 1 13 415539493427 5402013414551