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5402124343 = 71170157459
BaseRepresentation
bin1010000011111110…
…11110000000110111
3111221111001100110101
411001333132000313
542030420434333
62252014134531
7250604204440
oct50177360067
914844040411
105402124343
1123223a3a80
1210691b1447
136812650a5
1439365a2c7
152193d967d
hex141fde037

5402124343 has 8 divisors (see below), whose sum is σ = 6735116160. Its totient is φ = 4209447480.

The previous prime is 5402124341. The next prime is 5402124361. The reversal of 5402124343 is 3434212045.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 5402124343 - 21 = 5402124341 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5402124341) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35078653 + ... + 35078806.

It is an arithmetic number, because the mean of its divisors is an integer number (841889520).

Almost surely, 25402124343 is an apocalyptic number.

5402124343 is a deficient number, since it is larger than the sum of its proper divisors (1332991817).

5402124343 is a wasteful number, since it uses less digits than its factorization.

5402124343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 70157477.

The product of its (nonzero) digits is 11520, while the sum is 28.

The square root of 5402124343 is about 73499.1451855054. The cubic root of 5402124343 is about 1754.6406726406.

Adding to 5402124343 its reverse (3434212045), we get a palindrome (8836336388).

The spelling of 5402124343 in words is "five billion, four hundred two million, one hundred twenty-four thousand, three hundred forty-three".

Divisors: 1 7 11 77 70157459 491102213 771732049 5402124343