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54021941 = 471149403
BaseRepresentation
bin1100111000010…
…0111100110101
310202122121011122
43032010330311
5102312200231
65205513325
71224115241
oct316047465
9122577148
1054021941
1128548536
1216112845
13b265c5c
147263421
154b2177b
hex3384f35

54021941 has 4 divisors (see below), whose sum is σ = 55171392. Its totient is φ = 52872492.

The previous prime is 54021923. The next prime is 54021967. The reversal of 54021941 is 14912045.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-54021941 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 54021941.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (54021901) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 574655 + ... + 574748.

It is an arithmetic number, because the mean of its divisors is an integer number (13792848).

Almost surely, 254021941 is an apocalyptic number.

It is an amenable number.

54021941 is a deficient number, since it is larger than the sum of its proper divisors (1149451).

54021941 is a wasteful number, since it uses less digits than its factorization.

54021941 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1149450.

The product of its (nonzero) digits is 1440, while the sum is 26.

The square root of 54021941 is about 7349.9619726907. The cubic root of 54021941 is about 378.0275004954.

Adding to 54021941 its reverse (14912045), we get a palindrome (68933986).

The spelling of 54021941 in words is "fifty-four million, twenty-one thousand, nine hundred forty-one".

Divisors: 1 47 1149403 54021941