Base | Representation |
---|---|
bin | 111101011010110101101100… |
… | …1010011011000100110000011 |
3 | 2121211212102201102002212002110 |
4 | 1322311223121103120212003 |
5 | 1031302430310410011003 |
6 | 5153003335230350403 |
7 | 221536542411255225 |
oct | 17265533123304603 |
9 | 2554772642085073 |
10 | 540250402032003 |
11 | 14715a9aa714743 |
12 | 5071419265b403 |
13 | 1a25b5183c07a0 |
14 | 975a38a8ba415 |
15 | 426d245899a03 |
hex | 1eb5ad94d8983 |
540250402032003 has 32 divisors (see below), whose sum is σ = 803342990241792. Its totient is φ = 320702687107200.
The previous prime is 540250402031981. The next prime is 540250402032023. The reversal of 540250402032003 is 300230204052045.
It is not a de Polignac number, because 540250402032003 - 213 = 540250402023811 is a prime.
It is not an unprimeable number, because it can be changed into a prime (540250402032023) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 718044000 + ... + 718795997.
It is an arithmetic number, because the mean of its divisors is an integer number (25104468445056).
Almost surely, 2540250402032003 is an apocalyptic number.
540250402032003 is a deficient number, since it is larger than the sum of its proper divisors (263092588209789).
540250402032003 is a wasteful number, since it uses less digits than its factorization.
540250402032003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1436840355.
The product of its (nonzero) digits is 28800, while the sum is 30.
Adding to 540250402032003 its reverse (300230204052045), we get a palindrome (840480606084048).
The spelling of 540250402032003 in words is "five hundred forty trillion, two hundred fifty billion, four hundred two million, thirty-two thousand, three".
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