Base | Representation |
---|---|
bin | 110010010100100000… |
… | …000011111110011101 |
3 | 12011110111221020111221 |
4 | 302110200003332131 |
5 | 1341123421243123 |
6 | 40453240413341 |
7 | 3621640160110 |
oct | 622440037635 |
9 | 164414836457 |
10 | 54031040413 |
11 | 20a07128409 |
12 | a57aa77251 |
13 | 5130c3bb3c |
14 | 2887c44577 |
15 | 16136ec25d |
hex | c94803f9d |
54031040413 has 16 divisors (see below), whose sum is σ = 62689970304. Its totient is φ = 45607573440.
The previous prime is 54031040383. The next prime is 54031040417. The reversal of 54031040413 is 31404013045.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54031040413 is a prime.
It is a super-2 number, since 2×540310404132 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54031040417) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1765623 + ... + 1795963.
It is an arithmetic number, because the mean of its divisors is an integer number (3918123144).
Almost surely, 254031040413 is an apocalyptic number.
It is an amenable number.
54031040413 is a deficient number, since it is larger than the sum of its proper divisors (8658929891).
54031040413 is a wasteful number, since it uses less digits than its factorization.
54031040413 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 34212.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 54031040413 its reverse (31404013045), we get a palindrome (85435053458).
The spelling of 54031040413 in words is "fifty-four billion, thirty-one million, forty thousand, four hundred thirteen".
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