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5403133170257 is a prime number
BaseRepresentation
bin100111010100000001111…
…0101010101001001010001
3201010112102122022000222212
41032220003311111021101
51202011104042422012
615254055355241505
71065235451112254
oct116500365251121
921115378260885
105403133170257
1117a35018a7069
127331b6449295
133026898725b4
14149727ad909b
1595834216b22
hex4ea03d55251

5403133170257 has 2 divisors, whose sum is σ = 5403133170258. Its totient is φ = 5403133170256.

The previous prime is 5403133170203. The next prime is 5403133170263. The reversal of 5403133170257 is 7520713313045.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5276066586961 + 127066583296 = 2296969^2 + 356464^2 .

It is a cyclic number.

It is not a de Polignac number, because 5403133170257 - 242 = 1005086659153 is a prime.

It is not a weakly prime, because it can be changed into another prime (5403133110257) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2701566585128 + 2701566585129.

It is an arithmetic number, because the mean of its divisors is an integer number (2701566585129).

Almost surely, 25403133170257 is an apocalyptic number.

It is an amenable number.

5403133170257 is a deficient number, since it is larger than the sum of its proper divisors (1).

5403133170257 is an equidigital number, since it uses as much as digits as its factorization.

5403133170257 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 264600, while the sum is 41.

The spelling of 5403133170257 in words is "five trillion, four hundred three billion, one hundred thirty-three million, one hundred seventy thousand, two hundred fifty-seven".