Base | Representation |
---|---|
bin | 111101011011100010010001… |
… | …0000001000000100110010011 |
3 | 2121212012120202112211222211110 |
4 | 1322313010202001000212103 |
5 | 1031311012313433414103 |
6 | 5153115324314544403 |
7 | 221546501234120010 |
oct | 17267044201004623 |
9 | 2555176675758743 |
10 | 540346111232403 |
11 | 147197553aa6573 |
12 | 5072a843438103 |
13 | 1a26755bc82648 |
14 | 9760c69b2a707 |
15 | 427099806b403 |
hex | 1eb7122040993 |
540346111232403 has 64 divisors (see below), whose sum is σ = 838243248141312. Its totient is φ = 303213798074880.
The previous prime is 540346111232401. The next prime is 540346111232419. The reversal of 540346111232403 is 304232111643045.
It is not a de Polignac number, because 540346111232403 - 21 = 540346111232401 is a prime.
It is not an unprimeable number, because it can be changed into a prime (540346111232401) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 5806817425 + ... + 5806910477.
It is an arithmetic number, because the mean of its divisors is an integer number (13097550752208).
Almost surely, 2540346111232403 is an apocalyptic number.
540346111232403 is a deficient number, since it is larger than the sum of its proper divisors (297897136908909).
540346111232403 is a wasteful number, since it uses less digits than its factorization.
540346111232403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 100444.
The product of its (nonzero) digits is 207360, while the sum is 39.
Adding to 540346111232403 its reverse (304232111643045), we get a palindrome (844578222875448).
The spelling of 540346111232403 in words is "five hundred forty trillion, three hundred forty-six billion, one hundred eleven million, two hundred thirty-two thousand, four hundred three".
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