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54040501113 = 318013500371
BaseRepresentation
bin110010010101000100…
…001001101101111001
312011111011201220011020
4302111010021231321
51341133332013423
640454215253053
73622113452244
oct622504115571
9164434656136
1054040501113
1120a114aa375
12a58207a189
135132ba20a1
1428891c825b
15161446a4e3
hexc95109b79

54040501113 has 4 divisors (see below), whose sum is σ = 72054001488. Its totient is φ = 36027000740.

The previous prime is 54040501111. The next prime is 54040501133. The reversal of 54040501113 is 31110504045.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 54040501113 - 21 = 54040501111 is a prime.

It is not an unprimeable number, because it can be changed into a prime (54040501111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9006750183 + ... + 9006750188.

It is an arithmetic number, because the mean of its divisors is an integer number (18013500372).

Almost surely, 254040501113 is an apocalyptic number.

It is an amenable number.

54040501113 is a deficient number, since it is larger than the sum of its proper divisors (18013500375).

54040501113 is a wasteful number, since it uses less digits than its factorization.

54040501113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18013500374.

The product of its (nonzero) digits is 1200, while the sum is 24.

The spelling of 54040501113 in words is "fifty-four billion, forty million, five hundred one thousand, one hundred thirteen".

Divisors: 1 3 18013500371 54040501113