Base | Representation |
---|---|
bin | 1111101110100101010… |
… | …10000011110110110001 |
3 | 1220122212202122011110010 |
4 | 13313102222003312301 |
5 | 32323222204400301 |
6 | 1052131513525133 |
7 | 54020513003664 |
oct | 7672252036661 |
9 | 1818782564403 |
10 | 540405153201 |
11 | 1992036910a1 |
12 | 888987137a9 |
13 | 3bc63127354 |
14 | 1c2275376db |
15 | e0cce9a5d6 |
hex | 7dd2a83db1 |
540405153201 has 8 divisors (see below), whose sum is σ = 735870847104. Its totient is φ = 352604780720.
The previous prime is 540405153199. The next prime is 540405153203. The reversal of 540405153201 is 102351504045.
It is an interprime number because it is at equal distance from previous prime (540405153199) and next prime (540405153203).
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 540405153201 - 21 = 540405153199 is a prime.
It is not an unprimeable number, because it can be changed into a prime (540405153203) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1916330190 + ... + 1916330471.
It is an arithmetic number, because the mean of its divisors is an integer number (91983855888).
Almost surely, 2540405153201 is an apocalyptic number.
It is an amenable number.
540405153201 is a deficient number, since it is larger than the sum of its proper divisors (195465693903).
540405153201 is a wasteful number, since it uses less digits than its factorization.
540405153201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3832660711.
The product of its (nonzero) digits is 12000, while the sum is 30.
Adding to 540405153201 its reverse (102351504045), we get a palindrome (642756657246).
The spelling of 540405153201 in words is "five hundred forty billion, four hundred five million, one hundred fifty-three thousand, two hundred one".
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