Base | Representation |
---|---|
bin | 1111101110100111110… |
… | …11100010010001010001 |
3 | 1220122221020211021110001 |
4 | 13313103323202101101 |
5 | 32323243141331231 |
6 | 1052133555410001 |
7 | 54021162360625 |
oct | 7672373422121 |
9 | 1818836737401 |
10 | 540426511441 |
11 | 199214749933 |
12 | 888a38b3901 |
13 | 3bc67694a6b |
14 | 1c22a2d7185 |
15 | e0cecb8b61 |
hex | 7dd3ee2451 |
540426511441 has 2 divisors, whose sum is σ = 540426511442. Its totient is φ = 540426511440.
The previous prime is 540426511409. The next prime is 540426511451. The reversal of 540426511441 is 144115624045.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 540072130816 + 354380625 = 734896^2 + 18825^2 .
It is a cyclic number.
It is not a de Polignac number, because 540426511441 - 25 = 540426511409 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 540426511441.
It is not a weakly prime, because it can be changed into another prime (540426511451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270213255720 + 270213255721.
It is an arithmetic number, because the mean of its divisors is an integer number (270213255721).
Almost surely, 2540426511441 is an apocalyptic number.
It is an amenable number.
540426511441 is a deficient number, since it is larger than the sum of its proper divisors (1).
540426511441 is an equidigital number, since it uses as much as digits as its factorization.
540426511441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 76800, while the sum is 37.
The spelling of 540426511441 in words is "five hundred forty billion, four hundred twenty-six million, five hundred eleven thousand, four hundred forty-one".
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