Base | Representation |
---|---|
bin | 100111010100100100101… |
… | …1100101110010110101001 |
3 | 201010122110001000021202011 |
4 | 1032221021130232112221 |
5 | 1202021002042000113 |
6 | 15254411320435521 |
7 | 1065306422423236 |
oct | 116511134562651 |
9 | 21118401007664 |
10 | 5404301125033 |
11 | 17a3a51105848 |
12 | 733481618ba1 |
13 | 302814826bb5 |
14 | 1497d8c8678d |
15 | 958a1a2263d |
hex | 4ea4972e5a9 |
5404301125033 has 2 divisors, whose sum is σ = 5404301125034. Its totient is φ = 5404301125032.
The previous prime is 5404301124953. The next prime is 5404301125037. The reversal of 5404301125033 is 3305211034045.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2978068101264 + 2426233023769 = 1725708^2 + 1557637^2 .
It is a cyclic number.
It is not a de Polignac number, because 5404301125033 - 237 = 5266862171561 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5404301124986 and 5404301125004.
It is not a weakly prime, because it can be changed into another prime (5404301125037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2702150562516 + 2702150562517.
It is an arithmetic number, because the mean of its divisors is an integer number (2702150562517).
Almost surely, 25404301125033 is an apocalyptic number.
It is an amenable number.
5404301125033 is a deficient number, since it is larger than the sum of its proper divisors (1).
5404301125033 is an equidigital number, since it uses as much as digits as its factorization.
5404301125033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 5404301125033 its reverse (3305211034045), we get a palindrome (8709512159078).
The spelling of 5404301125033 in words is "five trillion, four hundred four billion, three hundred one million, one hundred twenty-five thousand, thirty-three".
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