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540433 is a prime number
BaseRepresentation
bin10000011111100010001
31000110100001
42003330101
5114243213
615330001
74410415
oct2037421
91013301
10540433
1133a043
12220901
1315bcaa
14100d45
15aa1dd
hex83f11

540433 has 2 divisors, whose sum is σ = 540434. Its totient is φ = 540432.

The previous prime is 540391. The next prime is 540437. The reversal of 540433 is 334045.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 506944 + 33489 = 712^2 + 183^2 .

It is a cyclic number.

It is not a de Polignac number, because 540433 - 29 = 539921 is a prime.

It is equal to p44605 and since 540433 and 44605 have the same sum of digits, it is a Honaker prime.

It is a self number, because there is not a number n which added to its sum of digits gives 540433.

It is not a weakly prime, because it can be changed into another prime (540437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270216 + 270217.

It is an arithmetic number, because the mean of its divisors is an integer number (270217).

2540433 is an apocalyptic number.

It is an amenable number.

540433 is a deficient number, since it is larger than the sum of its proper divisors (1).

540433 is an equidigital number, since it uses as much as digits as its factorization.

540433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 720, while the sum is 19.

The square root of 540433 is about 735.1414829813. The cubic root of 540433 is about 81.4542882908.

Adding to 540433 its reverse (334045), we get a palindrome (874478).

The spelling of 540433 in words is "five hundred forty thousand, four hundred thirty-three".