Base | Representation |
---|---|
bin | 11000100101000100110000… |
… | …01010011000011101000101 |
3 | 21002101011120210102222011010 |
4 | 30102202120022120131011 |
5 | 24041030230323430201 |
6 | 310542230515032433 |
7 | 14246004553461642 |
oct | 1422423012303505 |
9 | 232334523388133 |
10 | 54050421311301 |
11 | 16249722814168 |
12 | 608b40089b719 |
13 | 2420c18651c4c |
14 | d4c0a91c8dc9 |
15 | 63ae97482bd6 |
hex | 312898298745 |
54050421311301 has 8 divisors (see below), whose sum is σ = 72070273046464. Its totient is φ = 36032091891840.
The previous prime is 54050421311281. The next prime is 54050421311339. The reversal of 54050421311301 is 10311312405045.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 54050421311301 - 29 = 54050421310789 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54050421311501) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 380496076 + ... + 380638101.
It is an arithmetic number, because the mean of its divisors is an integer number (9008784130808).
Almost surely, 254050421311301 is an apocalyptic number.
It is an amenable number.
54050421311301 is a deficient number, since it is larger than the sum of its proper divisors (18019851735163).
54050421311301 is a wasteful number, since it uses less digits than its factorization.
54050421311301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 761157851.
The product of its (nonzero) digits is 7200, while the sum is 30.
Adding to 54050421311301 its reverse (10311312405045), we get a palindrome (64361733716346).
The spelling of 54050421311301 in words is "fifty-four trillion, fifty billion, four hundred twenty-one million, three hundred eleven thousand, three hundred one".
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