Base | Representation |
---|---|
bin | 111101011100110011011000… |
… | …0101100011011010010001011 |
3 | 2121212211020101022122200201112 |
4 | 1322321212300230123102023 |
5 | 1031321341040214423121 |
6 | 5153331333255240535 |
7 | 221565206003322341 |
oct | 17271466054332213 |
9 | 2555736338580645 |
10 | 540520303670411 |
11 | 1472544120a5439 |
12 | 5075855807914b |
13 | 1a27aacc66847c |
14 | 97694724cb991 |
15 | 42752909a075b |
hex | 1eb99b0b1b48b |
540520303670411 has 2 divisors, whose sum is σ = 540520303670412. Its totient is φ = 540520303670410.
The previous prime is 540520303670401. The next prime is 540520303670423. The reversal of 540520303670411 is 114076303025045.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 540520303670411 - 210 = 540520303669387 is a prime.
It is not a weakly prime, because it can be changed into another prime (540520303670401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270260151835205 + 270260151835206.
It is an arithmetic number, because the mean of its divisors is an integer number (270260151835206).
Almost surely, 2540520303670411 is an apocalyptic number.
540520303670411 is a deficient number, since it is larger than the sum of its proper divisors (1).
540520303670411 is an equidigital number, since it uses as much as digits as its factorization.
540520303670411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 302400, while the sum is 41.
Adding to 540520303670411 its reverse (114076303025045), we get a palindrome (654596606695456).
The spelling of 540520303670411 in words is "five hundred forty trillion, five hundred twenty billion, three hundred three million, six hundred seventy thousand, four hundred eleven".
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