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540613147 is a prime number
BaseRepresentation
bin100000001110010…
…001101000011011
31101200020222211011
4200032101220123
52101344110042
6125351114351
716253064424
oct4016215033
91350228734
10540613147
11258186728
121310729b7
1388004a49
1451b2864b
15326dba17
hex20391a1b

540613147 has 2 divisors, whose sum is σ = 540613148. Its totient is φ = 540613146.

The previous prime is 540613133. The next prime is 540613169. The reversal of 540613147 is 741316045.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 540613147 - 27 = 540613019 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (540413147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270306573 + 270306574.

It is an arithmetic number, because the mean of its divisors is an integer number (270306574).

Almost surely, 2540613147 is an apocalyptic number.

540613147 is a deficient number, since it is larger than the sum of its proper divisors (1).

540613147 is an equidigital number, since it uses as much as digits as its factorization.

540613147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10080, while the sum is 31.

The square root of 540613147 is about 23251.0891572847. The cubic root of 540613147 is about 814.6333789576.

The spelling of 540613147 in words is "five hundred forty million, six hundred thirteen thousand, one hundred forty-seven".