Base | Representation |
---|---|
bin | 110010010110100010… |
… | …111011110000010011 |
3 | 12011112220111020010121 |
4 | 302112202323300103 |
5 | 1341211212110403 |
6 | 40500504011111 |
7 | 3622534605061 |
oct | 622642736023 |
9 | 164486436117 |
10 | 54065347603 |
11 | 20a2452a963 |
12 | a58a460a97 |
13 | 5138091457 |
14 | 288c615031 |
15 | 16167273bd |
hex | c968bbc13 |
54065347603 has 2 divisors, whose sum is σ = 54065347604. Its totient is φ = 54065347602.
The previous prime is 54065347591. The next prime is 54065347717. The reversal of 54065347603 is 30674356045.
54065347603 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54065347603 is a prime.
It is a super-2 number, since 2×540653476032 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 54065347603.
It is not a weakly prime, because it can be changed into another prime (54065347103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27032673801 + 27032673802.
It is an arithmetic number, because the mean of its divisors is an integer number (27032673802).
Almost surely, 254065347603 is an apocalyptic number.
54065347603 is a deficient number, since it is larger than the sum of its proper divisors (1).
54065347603 is an equidigital number, since it uses as much as digits as its factorization.
54065347603 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 907200, while the sum is 43.
The spelling of 54065347603 in words is "fifty-four billion, sixty-five million, three hundred forty-seven thousand, six hundred three".
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