Base | Representation |
---|---|
bin | 11000100101100011000001… |
… | …11011110110001000111001 |
3 | 21002102201112111220202022201 |
4 | 30102301200323312020321 |
5 | 24041312022200414113 |
6 | 310553515403550201 |
7 | 14250121412366302 |
oct | 1422614073661071 |
9 | 232381474822281 |
10 | 54066674623033 |
11 | 162556033448a6 |
12 | 6092597b2b361 |
13 | 2422608a3a077 |
14 | d4cbaba597a9 |
15 | 63b5e9313cdd |
hex | 312c60ef6239 |
54066674623033 has 2 divisors, whose sum is σ = 54066674623034. Its totient is φ = 54066674623032.
The previous prime is 54066674622997. The next prime is 54066674623043. The reversal of 54066674623033 is 33032647666045.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 52073585737209 + 1993088885824 = 7216203^2 + 1411768^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54066674623033 is a prime.
It is not a weakly prime, because it can be changed into another prime (54066674623043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27033337311516 + 27033337311517.
It is an arithmetic number, because the mean of its divisors is an integer number (27033337311517).
Almost surely, 254066674623033 is an apocalyptic number.
It is an amenable number.
54066674623033 is a deficient number, since it is larger than the sum of its proper divisors (1).
54066674623033 is an equidigital number, since it uses as much as digits as its factorization.
54066674623033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 39191040, while the sum is 55.
The spelling of 54066674623033 in words is "fifty-four trillion, sixty-six billion, six hundred seventy-four million, six hundred twenty-three thousand, thirty-three".
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