Base | Representation |
---|---|
bin | 11000100101101011010101… |
… | …01100000101010100000011 |
3 | 21002110011001020120110201122 |
4 | 30102311222230011110003 |
5 | 24041400140101332324 |
6 | 310555534035222455 |
7 | 14250340042051361 |
oct | 1422655254052403 |
9 | 232404036513648 |
10 | 54071133230339 |
11 | 16257491093525 |
12 | 6093421147a2b |
13 | 2422b69680144 |
14 | d4d0b1c6c631 |
15 | 63b7aa977a5e |
hex | 312d6ab05503 |
54071133230339 has 2 divisors, whose sum is σ = 54071133230340. Its totient is φ = 54071133230338.
The previous prime is 54071133230273. The next prime is 54071133230407. The reversal of 54071133230339 is 93303233117045.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54071133230339 is a prime.
It is a super-2 number, since 2×540711332303392 (a number of 28 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 54071133230339.
It is not a weakly prime, because it can be changed into another prime (54011133230339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27035566615169 + 27035566615170.
It is an arithmetic number, because the mean of its divisors is an integer number (27035566615170).
Almost surely, 254071133230339 is an apocalyptic number.
54071133230339 is a deficient number, since it is larger than the sum of its proper divisors (1).
54071133230339 is an equidigital number, since it uses as much as digits as its factorization.
54071133230339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 612360, while the sum is 44.
The spelling of 54071133230339 in words is "fifty-four trillion, seventy-one billion, one hundred thirty-three million, two hundred thirty thousand, three hundred thirty-nine".
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