Base | Representation |
---|---|
bin | 100111010110111010001… |
… | …0101011011011010000111 |
3 | 201011010101111122000020111 |
4 | 1032231310111123122013 |
5 | 1202111234243200012 |
6 | 15301001050213451 |
7 | 1065544611645634 |
oct | 116556425333207 |
9 | 21133344560214 |
10 | 5409315600007 |
11 | 17a60946aa040 |
12 | 734440a24287 |
13 | 303133683157 |
14 | 149b52c3518b |
15 | 95a96d87ba7 |
hex | 4eb7455b687 |
5409315600007 has 32 divisors (see below), whose sum is σ = 6273498067200. Its totient is φ = 4612584787200.
The previous prime is 5409315600001. The next prime is 5409315600011. The reversal of 5409315600007 is 7000065139045.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5409315600007 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5409315600001) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8272219 + ... + 8902147.
It is an arithmetic number, because the mean of its divisors is an integer number (196046814600).
Almost surely, 25409315600007 is an apocalyptic number.
5409315600007 is a deficient number, since it is larger than the sum of its proper divisors (864182467193).
5409315600007 is a wasteful number, since it uses less digits than its factorization.
5409315600007 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 630367.
The product of its (nonzero) digits is 113400, while the sum is 40.
The spelling of 5409315600007 in words is "five trillion, four hundred nine billion, three hundred fifteen million, six hundred thousand, seven".
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