Base | Representation |
---|---|
bin | 1111101111101100101… |
… | …11110001111111011011 |
3 | 1220201102112010001212122 |
4 | 13313312113301333123 |
5 | 32330434102404321 |
6 | 1052311200331455 |
7 | 54041410011545 |
oct | 7676627617733 |
9 | 1821375101778 |
10 | 541004341211 |
11 | 1994909349a4 |
12 | 88a25313b8b |
13 | 3c02a2ca479 |
14 | 1c282d4c695 |
15 | e1158a78ab |
hex | 7df65f1fdb |
541004341211 has 2 divisors, whose sum is σ = 541004341212. Its totient is φ = 541004341210.
The previous prime is 541004341139. The next prime is 541004341223. The reversal of 541004341211 is 112143400145.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 541004341211 - 210 = 541004340187 is a prime.
It is a super-2 number, since 2×5410043412112 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (541004347211) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270502170605 + 270502170606.
It is an arithmetic number, because the mean of its divisors is an integer number (270502170606).
Almost surely, 2541004341211 is an apocalyptic number.
541004341211 is a deficient number, since it is larger than the sum of its proper divisors (1).
541004341211 is an equidigital number, since it uses as much as digits as its factorization.
541004341211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1920, while the sum is 26.
Adding to 541004341211 its reverse (112143400145), we get a palindrome (653147741356).
The spelling of 541004341211 in words is "five hundred forty-one billion, four million, three hundred forty-one thousand, two hundred eleven".
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