Search a number
-
+
54102125137 is a prime number
BaseRepresentation
bin110010011000101111…
…001110101001010001
312011122110200201102111
4302120233032221101
51341300121001022
640504300145321
73623462322154
oct623057165121
9164573621374
1054102125137
1120a4326a415
12a59a838241
13514289a2c8
142893469c9b
151619a8e477
hexc98bcea51

54102125137 has 2 divisors, whose sum is σ = 54102125138. Its totient is φ = 54102125136.

The previous prime is 54102125117. The next prime is 54102125141. The reversal of 54102125137 is 73152120145.

54102125137 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 47600766976 + 6501358161 = 218176^2 + 80631^2 .

It is a cyclic number.

It is not a de Polignac number, because 54102125137 - 219 = 54101600849 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 54102125099 and 54102125108.

It is not a weakly prime, because it can be changed into another prime (54102125117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27051062568 + 27051062569.

It is an arithmetic number, because the mean of its divisors is an integer number (27051062569).

Almost surely, 254102125137 is an apocalyptic number.

It is an amenable number.

54102125137 is a deficient number, since it is larger than the sum of its proper divisors (1).

54102125137 is an equidigital number, since it uses as much as digits as its factorization.

54102125137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8400, while the sum is 31.

The spelling of 54102125137 in words is "fifty-four billion, one hundred two million, one hundred twenty-five thousand, one hundred thirty-seven".