Base | Representation |
---|---|
bin | 11000100110101100010101… |
… | …01010111010110010100011 |
3 | 21002120111010020010101112112 |
4 | 30103112022222322302203 |
5 | 24042433122030044441 |
6 | 311023544500145535 |
7 | 14253013564540163 |
oct | 1423261252726243 |
9 | 232514106111475 |
10 | 54106029534371 |
11 | 16270269149211 |
12 | 609a13b9982ab |
13 | 242623b267c59 |
14 | d50a626a45a3 |
15 | 63c64e3734eb |
hex | 31358aabaca3 |
54106029534371 has 2 divisors, whose sum is σ = 54106029534372. Its totient is φ = 54106029534370.
The previous prime is 54106029534251. The next prime is 54106029534439. The reversal of 54106029534371 is 17343592060145.
54106029534371 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54106029534371 is a prime.
It is not a weakly prime, because it can be changed into another prime (54106025534371) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27053014767185 + 27053014767186.
It is an arithmetic number, because the mean of its divisors is an integer number (27053014767186).
Almost surely, 254106029534371 is an apocalyptic number.
54106029534371 is a deficient number, since it is larger than the sum of its proper divisors (1).
54106029534371 is an equidigital number, since it uses as much as digits as its factorization.
54106029534371 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2721600, while the sum is 50.
The spelling of 54106029534371 in words is "fifty-four trillion, one hundred six billion, twenty-nine million, five hundred thirty-four thousand, three hundred seventy-one".
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